给定一个字符串 s,找到 s 中最长的回文子串。你可以假设 s 的最大长度为 1000。

示例 1:

输入: "babad"
输出: "bab"
注意: "aba" 也是一个有效答案。

示例 2:

输入: "cbbd"
输出: "bb"

解法

class Solution:
    def longestPalindrome(self, s: str) -> str:
        str_len = len(s)
        max_len = 1
        start_index = 0

        dp = [[0]*str_len for _ in range(str_len)]

        for i in range(str_len):
            dp[i][i] = 1

        for j in range(str_len):
            for i in range(j - 1, -1, -1):
                if j == i+ 1 and s[j] == s[i]:
                    dp[i][j] = 2
                if j > i+1 and dp[i+1][j-1] > 0 and s[i] == s[j]:
                    dp[i][j] = dp[i + 1][j - 1] + 2
                if dp[i][j] > max_len:
                    max_len = dp[i][j]
                    start_index = i
        return s[start_index:start_index + max_len]